lstd.net
当前位置:首页 >> 已知函数F(x)=sin²ωx+√3sinωxsin(ωx+π/2)(ω... >>

已知函数F(x)=sin²ωx+√3sinωxsin(ωx+π/2)(ω...

已知函数f(x)=√3sin²ωx/2+sinωx/2cosωx/2(ωf(x)=√3sin²ωx/2+sinωx/2cosωx/2=√3/2(1-cosωx)+1/2sinωx=√3

ωx+√3sinωxsin(ωx+π/2)(ω>0)的最小正周期为(1)解析:∵函数f(x)=sin^2wx+√3sinwxsin(π/2+wx) (w>0) 的最小正周期为π f(x)=sin^2wx+√3sinwxsin(π

已知函数f(x)=sin^2ωx+√3sinωxsin(ωx+π/2)(ω>0f(x)=sin^2ωx+√3sinωxsin(ωx+π/2)=f(x)=sin^2ωx+√3sinωxcos(ωx)=

sin^2ωx+√3sinωxsin(ωx+π/2),(ω>0回答:f(x)=sin^2ωx+√3sinωxsin(ωx+π/2) =sin^2ωx+√3sinωxcosωx =1-cos^2wx+√3/2*sin2wx =1-

f(x)=sin²ωx+√3cosωx*cos(π/2-ωx)化简成f(x解f(x)=sin²wx+√3coswxcos(π/2-wx)=√3coswxsinwx+sin²wx=√3/2(2.

1、已知函数f(x)=sin²ωx+根号3sinωxsin[ωx+π1. f(x)=sin²ωx+根号3sinωxsin[ωx+π/2] =1/2-(1/2)cos2wx+√3sin

已知函数f(x)=sinωx+根号3sinωx乘sin(ωx+π/2)+2.f(x)=sin(2x-π/6)+1/2 因为x∈【0,2π/3】所以2x∈【0,4π/3】2x-π/6=【-π/6,π/2】所以f(x)∈

ωx+(根号3)sinωxsin(ωx+π/2)(ω》0)的最小正周期为f(X)=sin²ωx+3^½sinωx*sin(ωx+π/2)=1/2-1/2cos2ωx+3^½sin

已知函数f(x)=sin2ωx+3sinωxsin(ωx+π2)(ω>0)的最解答:解:(Ⅰ)∵函数f(x)=sin2ωx+3sinωxsin(ωx+π2)=sin2ωx+3sinωx 

已知函数f(x)=sin^2ωx+√3 sinωxsin(ωx+π/2)(ω>0= 2[(1/2)sin(ωx) + (√3/2)cos(ωx)]sin(ωx)= 2[cos(π/3)sin(ωx) + sin(π

相关文档
rpct.net | sgdd.net | famurui.com | lzth.net | xmjp.net | 网站首页 | 网站地图
All rights reserved Powered by www.lstd.net
copyright ©right 2010-2021。
内容来自网络,如有侵犯请联系客服。zhit325@qq.com